XYZ Mat 120 Module 1 Lesson 1 6 Part 2 — Transcript
Full transcript
- 0:00this is module 1 lesson 1.6 part
- 0:032. we stopped when we were talking about
- 0:07standard deviation now let's look at
- 0:08standard deviation for frequency
- 0:10distribution
- 0:11this time we have information
- 0:14in two different lists so i'm going to
- 0:16pull up my calculator i'm going to go to
- 0:17stat i'm going to go to enter
- 0:19and in l1 i'm going to put the aptitude
- 0:22scores
- 0:22so i put all the aptitude scores in l1
- 0:25then i'm going to put the frequencies in
- 0:28l2 so when i put all the frequencies in
- 0:30l2 now i have information
- 0:34in both lists l1 and l2
- 0:37then i'll go to stat i'll go over to
- 0:40calc and i'll hit enter
- 0:42make sure at this point that your list
- 0:43says l1
- 0:45and then your frequency list says l2 if
- 0:47your calculator does not then you have a
- 0:49little l2 right here above the two so
- 0:51we'll do
- 0:52second two to make sure that does say l2
- 0:55and then we'll come down here and
- 0:56calculate and the question is what is
- 0:59the sample standard deviation
- 1:01remember the sample standard deviation
- 1:03is the s sub
- 1:04x so that's going to be 1.77
- 1:09we rounded it to two decimal places
- 1:14the next example is we're doing a
- 1:16frequency distribution
- 1:18and we want an l1 to have our midpoints
- 1:22we want the frequencies in l2 so the
- 1:25midpoints i can find that by
- 1:27adding the values and dividing by 2. so
- 1:3050 plus 56 divided by 2 is 106 divided
- 1:34by 2
- 1:34which would be 53. so now when i go over
- 1:38here
- 1:39i'm going to put all the midpoints in l1
- 1:42and then i'm going to come over here and
- 1:44i'm going to put all of the frequencies
- 1:45in l2
- 1:46so 53 is going to be the first one then
- 1:5060. i'm adding 57 plus 3 and then 67
- 1:54because that's 64 plus 3
- 1:56and then 74 which is 71 plus 3
- 2:00and then 81 and then 85 plus 3 would be
- 2:0488 so those are
- 2:05all of my midpoints my frequencies
- 2:0910 18 15
- 2:138 7 and 3.
- 2:17and then when we do stat we do calc list
- 2:20one has l l1 as
- 2:21frequency has l2 then we'll calculate it
- 2:24and we're asked to find several things
- 2:26the sample mean
- 2:27we want two decimal places 66.196 would
- 2:32just simply be 66.2 or you could put
- 2:3566.20
- 2:36remember the mean is the very first
- 2:38thing you read the sample standard
- 2:40deviation is the s
- 2:429.907 would be 9.91
- 2:46so that's when we have the
- 2:50frequency distribution the empirical
- 2:53rule
- 2:53the empirical rule is a rule for data
- 2:56with a bell-shaped distribution
- 2:58and it's just what it says it's a rule
- 3:00about 68
- 3:02of values fall within one standard
- 3:04deviation of the mean
- 3:05you have to remember 68 goes to 1.
- 3:0895 of the values fall within two
- 3:10standard deviations of the mean
- 3:12and 99.7 fall within three standard
- 3:16deviations of the mean
- 3:17now what does that look like let me get
- 3:19rid of all this stuff
- 3:21and the mean is right here
- 3:24at the center so here's my mean it said
- 3:2768 of my data values fall within one
- 3:31standard deviation of the mean so they
- 3:34go from here to here
- 3:35half of them on the right side half of
- 3:37them on the left side
- 3:38and then we'll stretch it out two
- 3:41standard deviations of the mean
- 3:43contain about 95 percent of my data
- 3:46value so i'm stretching it out further
- 3:48and then almost all my data values 99.7
- 3:52percent fall within three standard
- 3:54deviations of the mean
- 3:56so that's almost all of my data values
- 3:59so just remember
- 4:0068 contains one standard deviation of
- 4:03the mean
- 4:0495 contains two and 99.7 contains
- 4:08three so let's look here at this problem
- 4:11we have adult males heights are normally
- 4:14distributed with a mean of 177 standard
- 4:16deviation of 7.4
- 4:18so what would be the range for the
- 4:22heights
- 4:23at 68 percent of the data well remember
- 4:2568
- 4:26is only one standard deviation so that
- 4:28would be
- 4:29the mean minus one times the standard
- 4:33deviation
- 4:34and the mean plus one times the standard
- 4:36deviation
- 4:37the mean is 177 the standard deviation
- 4:40is 7.4
- 4:41that's how we get our values 169.6 and
- 4:45184.4
- 4:4695 remember that's two standard
- 4:49deviations
- 4:50so we're going to do the mean minus 2
- 4:52times the standard deviation
- 4:54and the mean plus two times the standard
- 4:56deviation
- 4:57so that's going to stretch this out to
- 4:59162.2
- 5:01and 191.8 and then three standard
- 5:04deviations is 99.7 percent of the data
- 5:07that's the mean minus three times the
- 5:09standard deviation and the mean plus
- 5:11three times the standard deviation
- 5:12that stretches it out even further to
- 5:14154.8
- 5:16and 199.2
- 5:20then when we have a distribution here it
- 5:23says our
- 5:24mean score is 76. so let me just kind of
- 5:27start over here
- 5:28the mean score is 76 and the standard
- 5:30deviation
- 5:31is 14. what's the approximate percentage
- 5:33of students who scored between 62 and 76
- 5:36so right here
- 5:3876 is the mean and we only want this
- 5:40part
- 5:41if you remember for one standard
- 5:44deviation that was 68
- 5:47we only want half of it so here's one
- 5:49standard deviation they're asking us for
- 5:51half so we'll take half of 68 and that's
- 5:53how i get 34.
- 5:56then the next question is what is the
- 5:57approximate percentage who scored
- 5:58between 64 and 90
- 6:00well now we know that that is one
- 6:03standard deviation of the mean so that
- 6:0568 percent
- 6:07then it says what is the approximate
- 6:09percentage who scored less than 48
- 6:11and then what's approximate percentage
- 6:13who scored between 48 and 104. now if i
- 6:15go over here and if i go from 48
- 6:19to 104 i know that that is now two
- 6:22standard deviations of the mean
- 6:24and two standard deviations of the mean
- 6:26is 95
- 6:28so that's a total of 95 percent so if we
- 6:31think about this
- 6:32all of this is 95 so that's how i'm
- 6:35going to answer the last question
- 6:37but how do i answer the question that's
- 6:39less than 48 so less than 48 is just
- 6:42this right here
- 6:43so if the total is 95 1 minus 0.95
- 6:48is 5 and i only want this side of it so
- 6:51i'm going to take half of 5
- 6:53and i'm going to get 0.025 so that means
- 6:57that 0.025 is right here and .025 is
- 7:02right here
- 7:03because if you add those up together
- 7:04you'll get five percent
- 7:06you write that as a percentage 2.5
- 7:09percent
- 7:12and then the last part um we've got um
- 7:16the distribution of widget weights is
- 7:18bell-shaped the widget weights have a
- 7:20mean
- 7:20of 42 ounces a standard deviation of
- 7:22seven
- 7:23ninety-five percent remember ninety-five
- 7:26percent
- 7:27is two standard deviations of the mean
- 7:29so it would be the mean minus 2 times
- 7:31the standard deviation and the mean plus
- 7:322 times the standard deviation
- 7:34that's how we get 28 and 56. what
- 7:37percentage
- 7:38lies between 42 and 63.
- 7:42so it tells me the mean is 42. so that's
- 7:44my center
- 7:45and i want to know between 42 and 63.
- 7:48well here's one two three standard
- 7:51deviations of the mean
- 7:52since it's three standard deviations and
- 7:55i'm only looking at half of it because
- 7:57remember the other half is over here
- 7:59so half of 99.7 is
- 8:0349.85 percent
- 8:05and then the last one what percentage
- 8:07lies between 35 and 49
- 8:09well here's my 42. so 35
- 8:13and 49 would be back here and so that's
- 8:16only
- 8:167 to the right and 7 to the left so
- 8:18that's one standard deviation of the
- 8:20mean
- 8:21which would be 68 and all of that goes
- 8:25back to my
- 8:26rule for the empirical rule
- 8:29the last thing is consistency and what
- 8:31you need to know here
- 8:33standard deviations are more consistent
- 8:36if they're small
- 8:37if they're closer to the mean that means
- 8:38they're close they're consistent
- 8:40they're less consistent if they're large
- 8:42if they're farther from the mean
- 8:44so let's just look at this right here to
- 8:47determine if ricky is an effective
- 8:49method for treating pain a pilot study
- 8:50was carried out where a certified
- 8:52second second-degree degree reiki
- 8:55therapist provided treatment on
- 8:56volunteers pain was measured
- 8:58using vas immediately before and after
- 9:01this treatment
- 9:02so it says the readings before had a
- 9:05mean
- 9:05of 4.26 and a standard deviation of 2.19
- 9:09and then after the treatment the mean
- 9:12was 2.26 and the standard deviation is
- 9:152.09
- 9:16so is it more or less consistent before
- 9:20so the before had a standard deviation
- 9:24of 2.9
- 9:261 9 and then after it was 2.09 so it's
- 9:31less consistent because it's larger so
- 9:33if it's larger it's less consistent and
- 9:35all i'm doing is comparing my standard
- 9:37deviations that means i'm farther away
- 9:39i'm more spread out this time we're
- 9:42going to look at pulse rates from
- 9:44samples of females who are non-smokers
- 9:47but do drink alcohol the pulse rates
- 9:50who exercised had a mean of 74.15 a
- 9:53standard deviation 11.82
- 9:55after they ran in place for a minute
- 9:57they had a mean
- 9:58126 and a standard deviation of 25. so
- 10:01let's look at our standard deviations
- 10:02this one's 25 this one is 11.
- 10:05the pulse rates before they exercised
- 10:09so they before they exercise is smaller
- 10:11therefore it's more consistent
- 10:14than after they exercised because the
- 10:17number
- 10:17is smaller
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