What is a derivative? — Transcript
Full transcript
- 0:00is you know what is a derivative? Well,
- 0:02basically what a derivative is, it's a
- 0:04way of finding the instantaneous rate of
- 0:06change. And when you hear the word rate
- 0:08of change, what that means is referring
- 0:10to the slope. So, let me draw a diagram
- 0:12here for us. So, basically what we have
- 0:14is something that looks like this. Okay,
- 0:17we have a curve for example, right? And
- 0:20we have two points on the curve. Let's
- 0:22just say right here and right here. Now,
- 0:24if we go down to the x-axis, okay, this
- 0:27is going to be x. This distance right
- 0:28here is x. And if we go up to our
- 0:30function, this point here is going to be
- 0:33x comma f ofx. Okay, so when you put
- 0:36that x value into your function, you get
- 0:38out the y-value or the f ofx value.
- 0:40Right? Now, if we go a little bit
- 0:42further to the right, okay, let's just
- 0:44call this distance h. Okay, so you're
- 0:47with me so far. That means over here,
- 0:49we're going x plus h. Okay, x plus h.
- 0:52And if we go up to this point on our uh
- 0:55graph right here, we've got x plus h. If
- 0:57we put that into the function, the
- 0:59output or the y value is f ofx plus h.
- 1:03Okay, so all we've done is we've just
- 1:05written this in a real generic way, but
- 1:07what we have is we have two points on
- 1:09our curve. And now what we're going to
- 1:10do is we're going to find the slope,
- 1:14okay, between those two points. Okay?
- 1:16And when you find the slope, remember
- 1:18your slope formula from algebra. It's y2
- 1:20- y1 over x2 - x1, right? That's our
- 1:24slope formula. In this case, it's going
- 1:26to be f ofx + h.
- 1:31Okay, that's that y value minus f ofx,
- 1:34right? / x2 - x1. So that's going to be
- 1:37x + h.
- 1:39Okay, min - x. And you can see here that
- 1:42the uh
- 1:45x plus h - x, right? You can see that
- 1:48the x's are cancelling and we just have
- 1:49h in the denominator, right? But now
- 1:51let's take this a step further. So what
- 1:53we're doing right now is we're actually
- 1:54finding the slope between these two
- 1:56points which is the average rate of
- 1:58change. Okay, it's this average slope.
- 2:01But you can see that anywhere along this
- 2:02graph, the slope is constantly changing.
- 2:04Like here, okay, it's at an angle like
- 2:06so. Here it's a little bit less steep.
- 2:08Here it's even less steep. Here it's
- 2:09even less steep. Here it's even turning
- 2:11around and going the other direction.
- 2:12Right? So what we're doing is we're
- 2:14finding a formula for the instantaneous
- 2:17rate of change. Okay? The slope at any
- 2:20point along this curve. And the way we
- 2:22do that is we introduce limits. And it's
- 2:25the limit as h approaches zero. What
- 2:29that means is as this distance right
- 2:31here gets smaller and smaller and
- 2:32smaller, this point here in effect is
- 2:36moving along this curve until these two
- 2:39points are right on top of one another
- 2:43and that distance is zero. And so what
- 2:45we're getting now is we're getting the
- 2:48instantaneous rate of change instead of
- 2:50this average rate of change. So what
- 2:52you're seeing right here, and let me
- 2:53just rewrite it a little bit, is this is
- 2:55the limit as h approaches zero of f(x) +
- 2:59h - fx all / h. This is referred to as
- 3:04the difference quotient. Difference,
- 3:06remember, is subtracting. Quotient is
- 3:08dividing. So altogether, they call this
- 3:10the difference quotient. But when you
- 3:12get to the end of pre-calculus,
- 3:14beginning of calculus, they start to
- 3:16refer to this as fprime of x, which is
- 3:19the derivative. So don't get confused by
- 3:22the uh the word derivative. It's really
- 3:24just a formula for the slope of the
- 3:26tangent line. Okay? The line that just
- 3:28barely touches that graph at that one
- 3:29point. And it gives us the instantaneous
- 3:31rate of change. So let's get into uh a
- 3:35basic example. Now say for example, your
- 3:37function is like this. f ofx=
- 3:40x^2. Okay, so we've grown up uh as we've
- 3:43gone along in math and we know what f
- 3:45ofx= x^2 looks like. It's just a
- 3:47parabola like so. Right? But now what
- 3:50we're going to do is we're going to use
- 3:51our derivative. We're going to use our
- 3:52difference quotient to find the
- 3:54derivative. Okay, which is a formula for
- 3:56the slope of the tangent line at any
- 4:00point along this graph. So what we're
- 4:01going to do is let's go ahead and do
- 4:02these substitutions here. We're going to
- 4:04put in x + h, okay, squared minus f ofx,
- 4:10which is the original function. That's
- 4:11x^2 all / h. So if we simplify this, we
- 4:14get x^2 + 2 hx + h 2 - x^2 all / h. And
- 4:21it's the limit as h is approaching zero.
- 4:24Right? Now notice that the x^2s are
- 4:26cancel each other out. And then here we
- 4:28can factor out an h which gives us 2x +
- 4:31h all / h. So those h's cancel. And
- 4:34again, remember it's the limit as h
- 4:35approaches zero. If we put zero in for
- 4:37h, we're left with 2x. And this is our
- 4:40formula
- 4:43for our derivative, which remember the
- 4:44derivative is just a formula for the
- 4:46slope of the tangent line. So a simple
- 4:48example would be say we were interested
- 4:50in finding the slope at the point 2
- 4:544. Okay, right there. Okay, so we're
- 4:56trying to find the slope of that tangent
- 4:58line. Well, if we put in that x
- 5:00coordinate 2, okay, in for x here,
- 5:02that's going to be frime of 2, which is
- 5:05equal to 2 * 2, which is equal to 4. And
- 5:08again, remember this is a formula for
- 5:10our slope. So now we know that the slope
- 5:12is 4 and it goes through the point 24.
- 5:15Let's write an equation of the tangent
- 5:18line. So that's going to be y - y1 = m *
- 5:23x - x1. We're just going to use the
- 5:24point slope form. So this is going to be
- 5:26y - 4 = the slope which is also 4 * x -
- 5:31x coordinate of the point which is 2.
- 5:33And that's an equation for our tangent
- 5:36line. Okay? Like so.
- 5:40Now let's get into another example about
- 5:42you know we talked about how to find it.
- 5:44We talked about what it is and another
- 5:46example of why it's useful. So you
- 5:49probably remember from algebra 2 and uh
- 5:51pre-calculus when you were graphing
- 5:53polomials. So take for example this
- 5:55polomial here f ofx equ= uh x cubed - 4x
- 6:02right so one way we would graph this is
- 6:04we'd say all right let's see if we can
- 6:06factor this and find the zeros remember
- 6:08the zeros are just the
- 6:10x intercepts so if we factor this
- 6:12further we get x + 2 x -2 bring down the
- 6:16x if we set all these factors equal to
- 6:19zero you can see what we're getting is
- 6:21we're getting zero we're getting
- 6:24positive2 if we set that one to zero.
- 6:26And we're getting -2 if we set this
- 6:28group equal to zero. And we know the
- 6:30leading coefficient's positive. Okay,
- 6:32which tells us that the end behavior is
- 6:33going up to the right. And we know it's
- 6:36an odd degree. So that means it's going
- 6:37the opposite direction to the left. And
- 6:39we know the graph goes something like
- 6:41that through those points. But the
- 6:43question that students often times have
- 6:46is when you go through these points,
- 6:47like how high does that graph uh go
- 6:50before it turns around? Does it go way
- 6:52up here and then come back down here and
- 6:53go way back down here and or does it
- 6:55just go a little bit past the x-axis?
- 6:57You know, how do we find that out? How
- 6:59do we find those turning points? Well,
- 7:01what's interesting is is that when the
- 7:02graph bends, when it turns, okay, say
- 7:04for example, like this. What's the slope
- 7:06of the tangent line at that point where
- 7:08it turns? Well, you can see it's a
- 7:11horizontal line. So, the slope of that
- 7:13tangent line is zero. So what we're
- 7:15going to do is we're going to find the
- 7:16derivative of our equation and we're
- 7:17going to set that derivative equal to
- 7:19zero so we can find the points on the
- 7:21graph where the slope of the tangent
- 7:23line is equal to zero. Okay, so we're
- 7:25going to use our difference quotient
- 7:26again, our derivative formula right
- 7:27here. And so let's do that. So we've got
- 7:30x + h cubed - 4 * x + hus
- 7:37fx, which is original function. So
- 7:39that's going to be xqub - 4x all / h.
- 7:44Okay. Now if I simplify this, this comes
- 7:46out to x cub + 3x^2h + 3xh ^2. I'm using
- 7:52the binomial expansion theorem here.
- 7:54Distribute the -4. So that's -4x - 4h.
- 7:58Distribute the negative here. That gives
- 8:00us x cub + 4x. And this is all divided
- 8:04by h. Okay. And you can see we get a lot
- 8:06of cancellation. The x cubes are
- 8:08cancelling. The 4 x's are cancelling.
- 8:11And then if we factor out an h out of
- 8:13what remains here, we get 3x^2 + 3xh +
- 8:18h2 - 4 all / h. You can see those h's
- 8:23are cancelling. But remember, it's the
- 8:25limit as h approaches zero. Right? So if
- 8:28we put zero in now for h, this whole
- 8:30term is going to go to zero. This whole
- 8:32term is going to go to zero. and we're
- 8:33left with 3x^2 minus 4 is our
- 8:38derivative. Okay, that's a formula for
- 8:40our slope. But what we want to do is we
- 8:42want to find out where that slope is
- 8:43zero. Okay, that's where the graph is,
- 8:45you know, turning around or bending. And
- 8:47so what we're going to do is we're going
- 8:48to add four to both sides. Okay, so
- 8:50that's 3x^2. We're going to divide both
- 8:51sides by 3. So that's 4/3. We're going
- 8:54to take the square root of both sides.
- 8:56That gives us plus or minus, and I did
- 8:58this on the calculator for us. It's
- 8:591.15.
- 9:01Okay. Now, if we put 1.15 back into our
- 9:05original equation, what we get is 1.15,
- 9:09comma,
- 9:10uh, -3.08.
- 9:12And if we put in negative 1.15, we get
- 9:15positive 3.08.
- 9:18So, those are our turning points. So, if
- 9:19we graph this, you can see at 1.15,
- 9:22we're going to be up here at
- 9:24uh, let's see, we're going to be at
- 9:263.08. So, it's going to be right about
- 9:28there. And if we're at positive 1.5,
- 9:31we're going to be right about there. So
- 9:33that gives us a better idea, okay, of
- 9:37how high the graph is going and how low
- 9:40the graph is going. Otherwise, we're
- 9:41just kind of guessing. We don't really
- 9:43know where those extra are, those
- 9:45maximums and those minimums, right? So
- 9:47that's a a key point. And again, you can
- 9:49see where that graph is bending or
- 9:52turning or changing direction. That's
- 9:53where the slope of the tangent line is
- 9:55equal to zero. So key points to remember
- 9:57when you're uh learning about
- 10:00derivatives is you know what is a
- 10:01derivative? It's really a formula for
- 10:03the slope. How do we find the slope? We
- 10:05take these two points, okay, and we use
- 10:08our slope formula. But we take it a step
- 10:10further to go from the average rate of
- 10:12change to the instantaneous rate of
- 10:15change by using limits. And the limit as
- 10:18h gets smaller and smaller, it
- 10:19approaches zero. And then from there
- 10:22once you have the derivative you have a
- 10:23formula for the slope of the tangent
- 10:25line and you can you know use it in some
- 10:27of these applications like we talked
- 10:28about today. So I hope this video helped
- 10:30you understand what is a derivative, how
- 10:32is it useful you know and how to use it.
- 10:35Subscribe to the channel, check out more
- 10:36math tutoring videos on my YouTube
- 10:38channel, Mario's Math Tutoring and I
- 10:39look forward to helping you in the
- 10:40future videos. I'll talk to you soon.
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