The TWI Specification - Training Class CSWIP 3.2.1 Exam Preparation — Transcript

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1. 0:15They're talking about specification.
2. 0:20All right. The TWWI specification. Um.
3. 0:29All right.
4. 0:33What is specification? It means to state
5. 0:35explicitly or detail or to be specific.
6. 0:38A requirement specification is a set of
7. 0:42documented requirement to be satisfied
8. 0:44by material design product or service.
9. 0:49Then it said here specification is a
10. 0:51document that clearly and accurately
11. 0:54describe the essential requirement for
12. 0:56items material service including
13. 0:58procedure by which it can be determined
14. 1:01that the requirement have been met
15. 1:04and also it's a reference document is
16. 1:06provide guidance to test the
17. 1:08verification for verification of each
18. 1:10technical requirement the contract
19. 1:12document that must be adhered to which
20. 1:14specify how a design shall be
21. 1:17implemented. Yeah.
22. 1:19All right. The TW specification detail
23. 1:22requirement from material as they arrive
24. 1:24on site to find inspection and of end
25. 1:26product for senior inspector. The
26. 1:28specification has to be the defining
27. 1:30document that majority of your decision
28. 1:32are based on. Right. Uh TWW spec has 48
29. 1:36page and it will cover quality control
30. 1:39joint preparations
31. 1:41building detail set level equipment
32. 1:44consumable material defect repair NDT
33. 1:48inspection personnel report WPS WQT PWT
34. 1:55uh hydro test and also cy uh to me don't
35. 1:59worry too much about this as far as I
36. 2:02know they were not asking you about
37. 2:04this. Yeah. So, please only concentrate
38. 2:06on the topic we discussed during these
39. 2:09seven days. Yeah. All right.
40. 2:17All right. When using TWW a good
41. 2:19starting point to use index to find the
42. 2:21subject of your interest in. All right.
43. 2:23So, when you read the questions what
44. 2:25they talk about, if they talk about WPS,
45. 2:28you go to the you go find in the index
46. 2:30where is WPS the P number. Then from
47. 2:33there you open the spec. Yeah,
48. 2:37it save your time especially in exam.
49. 2:40Read the subject matter very carefully
50. 2:43as as it may make reference to another
51. 2:45sections. The majority of subject
52. 2:46require reference to TWSP but some will
53. 2:49not.
54. 2:51All right. Um for this one please find
55. 2:54the question. I think it's at the end of
56. 2:56the handout appendix. I'm not sure is it
57. 2:59appendix one or appendix two. Please
58. 3:01find the questions.
59. 3:03find the question first then let me know
60. 3:07all right I think it's at the end of
61. 3:09very end of the of the book uh
62. 3:14endings please find the question you got
63. 3:1610 questions let me know about this
64. 3:23all right
65. 3:26they write down specification there uh
66. 3:28specification questions if I'm not
67. 3:30mistaken
68. 3:30>> okay got
69. 3:33All right, look at question one and you
70. 3:36may find the answer on the page nine,
71. 3:38table one of the spec.
72. 3:58So
73. 4:01I think that is a table one
74. 4:11and
75. 4:13that one is less than and equal to that
76. 4:16the symbol four. Yeah. Okay.
77. 4:22So the answer goes to
78. 4:26um C. S is the let me check what is it S
79. 4:31for
80. 4:38so here we see that S is nominal but
81. 4:42thickness yeah
82. 4:45that one
83. 4:48nominal thickness and the symbol less
84. 4:51than or equal to is this one right so
85. 4:54that's why the answer goes to
86. 4:58C. All right. So, everybody okay with
87. 5:00that?
88. 5:00>> Yeah,
89. 5:01>> that's quite straightforward questions
90. 5:03and answer.
91. 5:05All right. Number two. In the case of
92. 5:07ferris double side by 12, which
93. 5:09inspection method should be employed
94. 5:10before second side well is welded?
95. 5:15Then we need to get the section 5.2 two
96. 5:19of the spec
97. 5:24and I think it's under joint preparation
98. 5:26detail
99. 5:32sorry it's under welding detail yeah
100. 5:34welding detail under the butwell here uh
101. 5:38look at the last sentence here
102. 5:41this shall be achieved by a suitable
103. 5:44means to clean sound metal this shall be
104. 5:46inspected before commencement of welding
105. 5:48on second side by both way and magnetic
106. 5:51particle special. So that will give us
107. 5:53the answer of question number two
108. 5:58which is um D delta. Yeah,
109. 6:07>> the answer goes to D visual and NPI
110. 6:10that's very straightforward. All right
111. 6:12number three, what will be the largest
112. 6:14lake dimension?
113. 6:17So largest leg length dimension meaning
114. 6:19here is maximum
115. 6:22maximum leg length and the smallest
116. 6:26dimensions here meaning the minimum
117. 6:30and the thickness apply or use here is
118. 6:3312 mm. So get 5.3 of this bag
119. 6:40here.
120. 6:42So the leg length here maximum t + 3 we
121. 6:46have 12 + 3. So we got 15. So that is
122. 6:50the maximum length required. And for the
123. 6:53throat thickness 12 * 0.7 12 * 0.7
124. 6:58then we got the answer which is
125. 7:02in this case the best answer goes to d.
126. 7:04So we got uh this one 12 + 3 and this
127. 7:08one is 12 * 0.7
128. 7:13as a minimum. All right.
129. 7:16All right. Look at question four.
130. 7:21Answer has been removed by grinding and
131. 7:23the inspection has proven acceptable.
132. 7:26The thickness of the joint is 25 mm and
133. 7:29the remote depth is 1 mm deep. Is this
134. 7:32acceptable?
135. 7:34All right, the answer given is C. But we
136. 7:36need to check what is from the spec,
137. 7:39right? So look at 5.6 from the spec.
138. 7:51All right. Look at under here
139. 7:55where the array has been repaired by
140. 7:57grinding. Confirmation that the
141. 7:59thickness of the parameter 3 is within
142. 8:01the permitted tolerance. This shall be a
143. 8:03thickness reduction of no more than 2%
144. 8:06of original material thickness. So they
145. 8:08ask for 2%
146. 8:11um from the original material thickness.
147. 8:13All right.
148. 8:15So now we do some calculations here.
149. 8:18So the thickness is 25 25 here. Then we
150. 8:22times 2%. So that will give us the
151. 8:27answer 0.5
152. 8:30mm. Yeah.
153. 8:32So 0.5 mm here is what the maximum
154. 8:38is a maximum reduction thickness. But
155. 8:41here we got
156. 8:431 mm deep which is over 0.5.
157. 8:48So that's why the answer goes to C not
158. 8:50acceptable as 0.5 is the maximum
159. 8:53reduction in thickness. Got it?
160. 8:56>> Yeah. All right.
161. 8:59That's number four. And then look at
162. 9:01number five. Uh continuous SAW is being
163. 9:04conducted on manufacturer of large I
164. 9:06beam 15 m in length. After completion of
165. 9:10each I beam the recycle flux
166. 9:12approximately 5 kilo has another 5 kilo
167. 9:14of new flux added before operation
168. 9:17continues again. Is this available?
169. 9:22All right. Then we look at 8.2 the
170. 9:24section 8.2 two of the spec
171. 9:32which is under storage and handling of
172. 9:35SAW.
173. 9:38All SAW flux shall be stored in
174. 9:40accordance with manufacturing
175. 9:41recommendation. as said that we flood
176. 9:43may be recycled to provide reused flood
177. 9:45is free from all contaminants like miski
178. 9:48and other for all recycled flood shall
179. 9:50be mixed equal amount new flats before
180. 9:53be used 50/50 ratio all right that
181. 9:56statement
182. 9:58give us the answer because of the they
183. 10:02put 5 kilo and 5 kilo that telling us
184. 10:06they got 50
185. 10:0950% use and 50%
186. 10:14new. All right. So that's where the
187. 10:16answer is C. This combination of mixing
188. 10:19new and use is adequate. Yeah. All
189. 10:21right. Look at question six.
190. 10:26We start on the testing of
191. 10:28circumferential pipe where 200 mm
192. 10:31diameter and 25 mm thickness has detect
193. 10:34lack of fusion 180 mm length.
194. 10:38All right.
195. 10:40diameter is 200 and lack of fusion is
196. 10:44180. So this is the two things we need
197. 10:47to look at here
198. 10:50regardless the thickness don't worry
199. 10:51about thickness here the contractor's
200. 10:54repair procedure want to carry out
201. 10:56repair what will be your cause of action
202. 10:59all right before we start we look at the
203. 11:02section 10.4 4 for repair but they ask
204. 11:05for repair here.
205. 11:07Okay, they ask for repair.
206. 11:10Look at 10.4
207. 11:14and repair defect repair end cut out
208. 11:18here in 10.4
209. 11:24reeling.
210. 11:26All right.
211. 11:28So repair well shall be limited to 25%
212. 11:32of the original well length. Okay 25%
213. 11:37original that is what
214. 11:40uh requirement maximum 25% if it exceed
215. 11:45anymore it must be cut out. Okay. Right
216. 11:49now we do a bit calculations here.
217. 12:41Example
218. 12:51here we have uh lack of fusion uh 180 mm
219. 12:56lf.
220. 12:58Uh the length is
221. 13:01180 mm
222. 13:04and we have the diameter here. diameter
223. 13:07of the pipe
224. 13:10diameter is uh 200 mm.
225. 13:14Now what we need to do is to find the
226. 13:17circumferential length. We need to get
227. 13:20to know what is the length of this
228. 13:23diameter. All right.
229. 13:26So we got
230. 13:36circumference length
231. 13:41it is circumferential or circumference
232. 13:44is the same meaning right
233. 13:46>> yes
234. 13:46>> okay so what formula we going to use pi
235. 13:50d
236. 13:51yeah pi diameter so pi is 3.14 4
237. 13:56times with 200
238. 13:59mm
239. 14:01from the diameter. Then we got roughly
240. 14:03about 628
241. 14:07mm. So that is circumferential length.
242. 14:09Here we got 628
243. 14:13mm.
244. 14:15Yeah. All right. Then the requirement
245. 14:16there is 25%
246. 14:20maximum allowable to repair if there is
247. 14:22any defect. So we times with 25%.
248. 14:29Let me get my calculator
249. 14:46628 time 25%. So we got roughly about
250. 14:51157.
251. 14:53So you got 157
252. 14:56mm. So that is maximum
253. 15:00defect
254. 15:02can be repaired.
255. 15:05Right? If we compare to what we have
256. 15:07here
257. 15:10we got 180. So that is over
258. 15:14than allowable maximum. All right.
259. 15:17So in that case the best answer goes to
260. 15:23Right.
261. 15:29The best answer goes to D. You insist a
262. 15:32complete cut out because of is beyond
263. 15:35repair. All right. Based on 25%
264. 15:39that exceeding 25%. Okay. All right.
265. 15:45We move to question number seven.
266. 15:50Uh the following parameters were used on
267. 15:5210 mm thick uh stainless steel 12 using
268. 15:57a thick process 12 volt 180 level speed
269. 16:0040 mm per minute witnessing this
270. 16:02operation what will be your cost of
271. 16:04action so they ask for oxenate stainless
272. 16:07here
273. 16:10and then get the section 14.4 which is
274. 16:14detail for stainless steel.
275. 16:19See section 14.4
276. 16:26here
277. 16:28in 14.4 welding details here we have a
278. 16:32different uh chromium content but we
279. 16:35assume that the maximum chromium content
280. 16:38here is 1.75. So that's the maximum
281. 16:41heat.
282. 16:43Yeah.
283. 16:48because the question is too generic. It
284. 16:50didn't telling us what is the chromium
285. 16:53content.
286. 16:55All right. Heat input formula is um
287. 17:00heat input equal to arc energy
288. 17:04times
289. 17:07time k. Yeah. So here the tig the k
290. 17:11factor
291. 17:13k factor is 0.6. six. All right. Now we
292. 17:18have volt which is 12
293. 17:23*
294. 17:25180
295. 17:26amps
296. 17:28time 602. Then we divide by
297. 17:3440 mm*
298. 17:381,000
299. 17:40and then we times with 0.6 the k factor
300. 17:44of tig. Yeah. All right. Let me check.
301. 17:4912 * 1 180
302. 17:54* 60. So we have 129.
303. 17:59We have 1290
304. 18:04129,000 divided by 40,000.
305. 18:10All right. We can we remove this.
306. 18:14All right. And that time 0.6 Six.
307. 18:22Sorry. 129.
308. 18:25Let me check. 12 *
309. 18:30180 * 60
310. 18:35129600. 1296. Sorry about this. 129600.
311. 18:41So, all right. We remove two zero here.
312. 18:48So we remove 2 0 divided by
313. 18:52400.
314. 18:57All right. So we got here we got 3.24
315. 19:03then times with 0.6.
316. 19:10So we got
317. 19:13heat input here 1.94
318. 19:17kilojoule. All right
319. 19:20per mm. So from the spec
320. 19:25the maximum heat input from the spec for
321. 19:29this type of material is 1.9
322. 19:324 kilojoule.
323. 19:34But what we have in our calculations
324. 19:37sorry 1.75 so 1.75
325. 19:42that's what in our spec
326. 19:45right spec only request request maximum
327. 19:481.75
328. 19:50where
329. 19:51during
330. 19:54uh welding
331. 19:55when we when they record the parameters
332. 19:58they found out that it's more than 1.75
333. 20:01in this case we got 1.94 so that is
334. 20:04higher, right? So that's where the
335. 20:07answer goes to goes to A. All right, got
336. 20:11it.
337. 20:14All right, look at question eight. Uh, a
338. 20:17procedure was conducted in PF position.
339. 20:20So PF position is vertical up,
340. 20:25right? Vertical up with MMA in 15 mm
341. 20:29thickness carbon manganese. The
342. 20:30following test were conducted
343. 20:33harness micro sideband tensile and
344. 20:36impact. All right. When we have impact
345. 20:40meaning they are looking for toughness
346. 20:46toughness value. All right. So in order
347. 20:49to answer this, look at section 17.9.
348. 21:05All right.
349. 21:08Welding position. In all cases when
350. 21:10impact test are not required, the
351. 21:12position of the test will qualify for
352. 21:14all welding positions.
353. 21:16When impact test required the test piece
354. 21:18carried out vertical up position will
355. 21:20only qualify for vertical arms meaning
356. 21:23they not allowed for other position
357. 21:25because of there is impact impact test.
358. 21:29So they not it will not cover other
359. 21:31positions.
360. 21:33So that will give us answer of
361. 21:39B.
362. 21:41The procedure can only use for original
363. 21:44test positions. Okay. Not for other
364. 21:47positions.
365. 21:49All right. Question nine. Quench and
366. 21:52temper steel has to undergo post
367. 21:54treatment. Which of the following is
368. 21:56correct?
369. 21:59In order to answer this, we look at
370. 22:01under post treatment under section 19.3.
371. 22:17All right. So we have uh in this
372. 22:21uh PWT here we got carbon manganese
373. 22:25steel qu and temper and also duplex
374. 22:28stainless. So what we have in carbon
375. 22:31manganese said the temperature is 650°.
376. 22:36All right but in quench and temper it
377. 22:38say shall not exceed 600. So the
378. 22:41difference between carbon manginis and
379. 22:43quench is the maximum temperature. The
380. 22:46quench temper is not more than 600° C.
381. 22:51Heating rate shall be controlled from
382. 22:54300. Cooling rate controlled from 300.
383. 22:57Insulation thermouple shall not be
384. 22:59removed until the component temperature
385. 23:02drop below 110° C. Right?
386. 23:06So
387. 23:08that will give us the answer of
388. 23:13B.
389. 23:15Here we got heating rate from 300.
390. 23:17That's correct. Soaking 580 that's okay
391. 23:21because our maximum given is 600.
392. 23:24Cooling rate control 300 correct and
393. 23:27thermocouple remove below 110° C.
394. 23:31But if you look at a that's wrong
395. 23:33because of it's more than 300 cooling
396. 23:36also more than 300 but the soap
397. 23:39temperature is okay.
398. 23:41See heating rate control 220°
399. 23:45C soap temperature 450.
400. 23:50All right. And remove automocapp at this
401. 23:52point. So that is wrong here. Heating
402. 23:55control. All right. This is totally
403. 23:56wrong. Okay.
404. 24:00All right. Question 10. The last one.
405. 24:03A quench temperature 40 mm thick require
406. 24:07preheat temperatures 100° and control
407. 24:09into pass temperature of 100°.
408. 24:12The SA process be used. The heat input
409. 24:14must be controlled. Which of the
410. 24:16following confirms?
411. 24:19All right. Look at uh table 6A.
412. 24:23Right. Table 6 A.
413. 24:45here.
414. 24:51All right.
415. 24:58So, the thickness is 40 mm. So, it must
416. 25:02be here.
417. 25:04And the preheat temperature required is
418. 25:06100° here.
419. 25:09Then from here we got the maximum. Is it
420. 25:12maximum? Yeah. Sorry. It's a minimum.
421. 25:14Minimum heat input required is 3.4.
422. 25:17It's here. Yeah. All right.
423. 25:25Then when you do a calculations, C is
424. 25:28the best answer, right?
425. 25:30Because from this 32 volt the heat input
426. 25:3332
427. 25:36* 620*
428. 25:41uh per minute here then we times with 60
429. 25:45divided by
430. 25:48350 *
431. 25:501,000
432. 25:52because saw the K factor
433. 25:55K factor is equal to one. So it doesn't
434. 25:59matter whatever arc energy you got here.
435. 26:04The arc energy you got here you times
436. 26:06one the heating pool still the same.
437. 26:08Yeah,
438. 26:13right. 32 * 620 * 60. You got that?
439. 26:21Divided by 350
440. 26:261 2 3. So we got 3.4. 4
441. 26:30from here we got
442. 26:323.4 kiloj
443. 26:36and the rest I think all these a b and d
444. 26:40all is below then 3.4 four. So that's
445. 26:43where the answer is C is the best. Okay.