Operations on Regular Languages — Transcript
Full transcript
- 0:05hello everyone welcome to the next
- 0:06lecture in theory of computation and in
- 0:08this lecture we will be discussing about
- 0:11some of the operations on regular
- 0:13languages all right so let's get started
- 0:16okay so here are the operations that we
- 0:18are going to discuss Union concatenation
- 0:20and star so let's start with Union so
- 0:23the formal definition of union is given
- 0:25here a union B is equal to X such that X
- 0:28belongs to a or X belongs to B so this
- 0:32Union operation is exactly the same like
- 0:34you perform your union operation on sets
- 0:37so suppose you have two language sets
- 0:39namely A and B then the union of A and B
- 0:42would actually mean anything X such that
- 0:46X could either belong to the set a or it
- 0:50could belong to the set B so it
- 0:52basically means everything from A and B
- 0:55okay that is Union and coming to the
- 0:57next one that is
- 0:58concatenation a concatenation b
- 1:00concatenation is denoted by the small
- 1:02circle and is equal it is equal to XY
- 1:06such that X belongs to a and Y belongs
- 1:09to B this basically means that joining
- 1:12two symbols together when you join two
- 1:16or more strings or symbols together that
- 1:18is what we mean by concatenation so
- 1:21suppose you
- 1:22have X which is an element of a and Y
- 1:26which is an element of B and you join
- 1:28them together like this X y that is
- 1:30known as
- 1:32concatenation and uh the next one is
- 1:35star so star operation unlike Union and
- 1:38conation in Star operation we have only
- 1:40one set so performing the star operation
- 1:44on set a means X1 X2 X3 up to XK such
- 1:49that K greater than or equal to zero and
- 1:53each X of I belongs to a so don't worry
- 1:57about this long definition it only means
- 1:59that you you
- 2:00take as many symbols that you want from
- 2:04your set a and you just join them
- 2:06together in any way you like that is
- 2:09what you mean by star so all these three
- 2:12will become more clear when we take an
- 2:14example that we are going to do below
- 2:16that will make it even clearer all right
- 2:19so let's take an example so here I'm
- 2:22taking an example where I have two sets
- 2:25A and B where a is equal to a set where
- 2:29I have the
- 2:32elements PQ and
- 2:35R and then I have another set called B
- 2:39which also has two elements T and
- 2:44UV so we have these two sets and let's
- 2:47perform Union concatenation and star on
- 2:48these two sets so first of all let's
- 2:51perform Union a union B what would this
- 2:57be so a un b as we saw in the definition
- 3:01X such that X belongs to a or X belongs
- 3:03to B so basically it means everything
- 3:05from A and B just put all these elements
- 3:08together from A and B so from a we have
- 3:13PQ and R and from B you have t and UV T
- 3:19and UV so this is the union operation
- 3:23everything from set a and set B put
- 3:25together that is the union operation and
- 3:28coming to the next one we have the
- 3:30concatenation concatenation of A and B
- 3:33so what is the concatenation of A and B
- 3:36so as I told you concatenation means
- 3:38joining two or more symbols or strings
- 3:41together so here in a we have PQ and R
- 3:44and in B we have t and UV so I should
- 3:47join XY such that X belongs to a and Y
- 3:50belongs to B that means one element from
- 3:52a and another element from B should be
- 3:54joined so how can I perform the joining
- 3:56I could join PQ and T
- 4:00PQ and T I have joined them together
- 4:03that means I have concatenated it then
- 4:06in the same way I can join PQ and
- 4:09UV PQ UV and in the same way I can join
- 4:13R and T R and T and then I can also join
- 4:18R and UV R and UV so here we have
- 4:23performed the concatenation of A and B
- 4:25where the first element is from a second
- 4:27is from B and we have joined them
- 4:29together so that is a
- 4:31concatenation and coming to
- 4:33the last one which is star operation a
- 4:38star so what is a star so as I told you
- 4:41in Star operation there is only one set
- 4:43involved so a star means I can take as
- 4:47many symbols from that set and I can
- 4:50join them together in any way I like so
- 4:53I'm dealing with a a star so in a star
- 4:57what are the elements that I can have so
- 5:00I would first write Epsilon Epsilon as I
- 5:03already told you in the first lecture it
- 5:04means the empty string so empty string
- 5:06also is a part of a star all right and
- 5:09the second one would be PQ just by
- 5:11itself I can write it and R just by
- 5:16itself all right now let me join PQ andr
- 5:19I can join PQ andr right I can also put
- 5:23R first and then PQ R and then
- 5:28PQ or I could put I could join PQ with
- 5:31itself PQ PQ or I could join r with
- 5:35itself like this r r or I could join PQ
- 5:38three times PQ PQ
- 5:41and PQ or I could even oh sorry there
- 5:45should be no comma over here this is PQ
- 5:50PQ
- 5:52and
- 5:53PQ means I'm joining it together and I
- 5:56can also join R three times r r r and it
- 6:00goes on this actually will be an
- 6:01infinite set it could have infinite
- 6:03number of elements so that is how we
- 6:05perform Union concatenation and star all
- 6:08right so I hope this was clear now there
- 6:11are two important theorems that you need
- 6:13to
- 6:14remember which I will be discussing now
- 6:17all right so here are the two theorems
- 6:19the first theorem says that the class of
- 6:21regular languages is closed under Union
- 6:24so what does this mean this means that
- 6:27if you have two regular languages let's
- 6:29say suppose A and B are two regular
- 6:31languages and if you perform the union
- 6:33of A and B you perform the union of A
- 6:36and B which are regular languages then
- 6:38the union of A and B is also a regular
- 6:41language that means the union of two
- 6:43regular languages is also a regular
- 6:45language that is what it means and then
- 6:47the second theorem says that the class
- 6:49of regular languages is closed under
- 6:51concatenation in the same way if you
- 6:53have two languages A and B which are
- 6:56regular and if you perform the
- 6:58concatenation of them then then the
- 6:59concatenation of those two languages
- 7:01will also be regular the concatenation
- 7:03of two regular languages will also be a
- 7:06regular language so that is the meaning
- 7:09of these two theorems so I'll not be
- 7:12doing the proof of these two theorems
- 7:14and if you won the proof you can leave a
- 7:17comment in the comment section below so
- 7:18I will be discussing it in a later
- 7:20lecture so I hope this we clear to you
- 7:25about the operations that we perform on
- 7:27regular languages which are Union SK
- 7:29nation and star so thank you for
- 7:31watching and see you in the next
- 7:37[Music]
- 7:43video
About this transcript
This page contains the full transcript of Operations on Regular Languages by Neso Academy, generated from the public captions YouTube serves with the video. The transcript has 1,236 words across 163 segments, with the original timestamps preserved so you can click any line to jump to that moment in the embedded player.
What you can do with it
Use the transcript to take notes, quote the speaker, build a study guide, generate a summary with ChatGPT or Claude via the YouTube Summary tool, or export it as a timed subtitle file with YouTube to SRT. You can also re-open it in the transcriber to translate the transcript into 100+ languages.
Free YouTube transcript tool
YouTube2Text is a free YouTube transcript generator — no signup, no daily limit. Paste any YouTube link and get the full transcript instantly, with timestamps, click-to-jump, translation to 100+ languages, AI prompts for ChatGPT, Claude, and Gemini, and exports to TXT, SRT, VTT, or Markdown.