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Operations on Regular Languages — Transcript

by Neso Academy · 1,236 words · 163 segments · language en · Watch on YouTube

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  1. 0:05hello everyone welcome to the next
  2. 0:06lecture in theory of computation and in
  3. 0:08this lecture we will be discussing about
  4. 0:11some of the operations on regular
  5. 0:13languages all right so let's get started
  6. 0:16okay so here are the operations that we
  7. 0:18are going to discuss Union concatenation
  8. 0:20and star so let's start with Union so
  9. 0:23the formal definition of union is given
  10. 0:25here a union B is equal to X such that X
  11. 0:28belongs to a or X belongs to B so this
  12. 0:32Union operation is exactly the same like
  13. 0:34you perform your union operation on sets
  14. 0:37so suppose you have two language sets
  15. 0:39namely A and B then the union of A and B
  16. 0:42would actually mean anything X such that
  17. 0:46X could either belong to the set a or it
  18. 0:50could belong to the set B so it
  19. 0:52basically means everything from A and B
  20. 0:55okay that is Union and coming to the
  21. 0:57next one that is
  22. 0:58concatenation a concatenation b
  23. 1:00concatenation is denoted by the small
  24. 1:02circle and is equal it is equal to XY
  25. 1:06such that X belongs to a and Y belongs
  26. 1:09to B this basically means that joining
  27. 1:12two symbols together when you join two
  28. 1:16or more strings or symbols together that
  29. 1:18is what we mean by concatenation so
  30. 1:21suppose you
  31. 1:22have X which is an element of a and Y
  32. 1:26which is an element of B and you join
  33. 1:28them together like this X y that is
  34. 1:30known as
  35. 1:32concatenation and uh the next one is
  36. 1:35star so star operation unlike Union and
  37. 1:38conation in Star operation we have only
  38. 1:40one set so performing the star operation
  39. 1:44on set a means X1 X2 X3 up to XK such
  40. 1:49that K greater than or equal to zero and
  41. 1:53each X of I belongs to a so don't worry
  42. 1:57about this long definition it only means
  43. 1:59that you you
  44. 2:00take as many symbols that you want from
  45. 2:04your set a and you just join them
  46. 2:06together in any way you like that is
  47. 2:09what you mean by star so all these three
  48. 2:12will become more clear when we take an
  49. 2:14example that we are going to do below
  50. 2:16that will make it even clearer all right
  51. 2:19so let's take an example so here I'm
  52. 2:22taking an example where I have two sets
  53. 2:25A and B where a is equal to a set where
  54. 2:29I have the
  55. 2:32elements PQ and
  56. 2:35R and then I have another set called B
  57. 2:39which also has two elements T and
  58. 2:44UV so we have these two sets and let's
  59. 2:47perform Union concatenation and star on
  60. 2:48these two sets so first of all let's
  61. 2:51perform Union a union B what would this
  62. 2:57be so a un b as we saw in the definition
  63. 3:01X such that X belongs to a or X belongs
  64. 3:03to B so basically it means everything
  65. 3:05from A and B just put all these elements
  66. 3:08together from A and B so from a we have
  67. 3:13PQ and R and from B you have t and UV T
  68. 3:19and UV so this is the union operation
  69. 3:23everything from set a and set B put
  70. 3:25together that is the union operation and
  71. 3:28coming to the next one we have the
  72. 3:30concatenation concatenation of A and B
  73. 3:33so what is the concatenation of A and B
  74. 3:36so as I told you concatenation means
  75. 3:38joining two or more symbols or strings
  76. 3:41together so here in a we have PQ and R
  77. 3:44and in B we have t and UV so I should
  78. 3:47join XY such that X belongs to a and Y
  79. 3:50belongs to B that means one element from
  80. 3:52a and another element from B should be
  81. 3:54joined so how can I perform the joining
  82. 3:56I could join PQ and T
  83. 4:00PQ and T I have joined them together
  84. 4:03that means I have concatenated it then
  85. 4:06in the same way I can join PQ and
  86. 4:09UV PQ UV and in the same way I can join
  87. 4:13R and T R and T and then I can also join
  88. 4:18R and UV R and UV so here we have
  89. 4:23performed the concatenation of A and B
  90. 4:25where the first element is from a second
  91. 4:27is from B and we have joined them
  92. 4:29together so that is a
  93. 4:31concatenation and coming to
  94. 4:33the last one which is star operation a
  95. 4:38star so what is a star so as I told you
  96. 4:41in Star operation there is only one set
  97. 4:43involved so a star means I can take as
  98. 4:47many symbols from that set and I can
  99. 4:50join them together in any way I like so
  100. 4:53I'm dealing with a a star so in a star
  101. 4:57what are the elements that I can have so
  102. 5:00I would first write Epsilon Epsilon as I
  103. 5:03already told you in the first lecture it
  104. 5:04means the empty string so empty string
  105. 5:06also is a part of a star all right and
  106. 5:09the second one would be PQ just by
  107. 5:11itself I can write it and R just by
  108. 5:16itself all right now let me join PQ andr
  109. 5:19I can join PQ andr right I can also put
  110. 5:23R first and then PQ R and then
  111. 5:28PQ or I could put I could join PQ with
  112. 5:31itself PQ PQ or I could join r with
  113. 5:35itself like this r r or I could join PQ
  114. 5:38three times PQ PQ
  115. 5:41and PQ or I could even oh sorry there
  116. 5:45should be no comma over here this is PQ
  117. 5:50PQ
  118. 5:52and
  119. 5:53PQ means I'm joining it together and I
  120. 5:56can also join R three times r r r and it
  121. 6:00goes on this actually will be an
  122. 6:01infinite set it could have infinite
  123. 6:03number of elements so that is how we
  124. 6:05perform Union concatenation and star all
  125. 6:08right so I hope this was clear now there
  126. 6:11are two important theorems that you need
  127. 6:13to
  128. 6:14remember which I will be discussing now
  129. 6:17all right so here are the two theorems
  130. 6:19the first theorem says that the class of
  131. 6:21regular languages is closed under Union
  132. 6:24so what does this mean this means that
  133. 6:27if you have two regular languages let's
  134. 6:29say suppose A and B are two regular
  135. 6:31languages and if you perform the union
  136. 6:33of A and B you perform the union of A
  137. 6:36and B which are regular languages then
  138. 6:38the union of A and B is also a regular
  139. 6:41language that means the union of two
  140. 6:43regular languages is also a regular
  141. 6:45language that is what it means and then
  142. 6:47the second theorem says that the class
  143. 6:49of regular languages is closed under
  144. 6:51concatenation in the same way if you
  145. 6:53have two languages A and B which are
  146. 6:56regular and if you perform the
  147. 6:58concatenation of them then then the
  148. 6:59concatenation of those two languages
  149. 7:01will also be regular the concatenation
  150. 7:03of two regular languages will also be a
  151. 7:06regular language so that is the meaning
  152. 7:09of these two theorems so I'll not be
  153. 7:12doing the proof of these two theorems
  154. 7:14and if you won the proof you can leave a
  155. 7:17comment in the comment section below so
  156. 7:18I will be discussing it in a later
  157. 7:20lecture so I hope this we clear to you
  158. 7:25about the operations that we perform on
  159. 7:27regular languages which are Union SK
  160. 7:29nation and star so thank you for
  161. 7:31watching and see you in the next
  162. 7:37[Music]
  163. 7:43video

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