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Ex: Quadratic Function Review — Transcript

by Mathispower4u · 1,163 words · 139 segments · language en · Watch on YouTube

Full transcript

  1. 0:00IN THIS VIDEO WE'LL REVIEW
  2. 0:02HOW TO FIND ALL THE MAJOR COMPONENTS
  3. 0:04OF A QUADRATIC FUNCTION
  4. 0:05AS WELL AS HOW TO GRAPH A QUADRATIC FUNCTION.
  5. 0:08HERE WE'RE GIVEN F OF X = -2/SQUARED + 5X + 3.
  6. 0:13OUR FIRST QUESTION IS, DOES THE PARABOLA OPEN UP OR DOWN.
  7. 0:16THIS IS DETERMINED BY THE SIGN OF "A"
  8. 0:19OR THE SIGN OF THE LEADING COEFFICIENT.
  9. 0:21HERE "A" EQUAL TO -2
  10. 0:24AND SINCE "A" IS NEGATIVE THE PARABOLA OPENS DOWN.
  11. 0:31NEXT, WE'RE ASKED TO DETERMINE THE EQUATION
  12. 0:32OF THE AXIS OF SYMMETRY.
  13. 0:34FOR THIS WE'LL USE THE EQUATION X = -B DIVIDED BY 2A.
  14. 0:39AGAIN, "A" IS EQUAL TO -2 AND B IS EQUAL TO +5.
  15. 0:46SO OUR EQUATION WILL BE X = -B DIVIDED BY 2A.
  16. 0:52WELL B IS EQUAL TO 5 AND "A" EQUAL TO -2 SO WE HAVE 2 x -2.
  17. 1:00SO HERE WE HAVE -5 DIVIDED BY -4 WHICH WILL BE +5/4.
  18. 1:06SO THE EQUATION OF THE AXIS OF SYMMETRY IS X = 5/4.
  19. 1:13NEXT, WE'RE ASKED TO DETERMINE THE COORDINATES OF THE VERTEX.
  20. 1:16REMEMBER THE VERTEX LIES ON THE AXIS OF SYMMETRY
  21. 1:19SO THE X COORDINATE OF THE VERTEX WILL BE 5/4
  22. 1:24AND THEN TO FIND THE Y COORDINATE
  23. 1:27WE NEED TO DETERMINE F OF 5/4
  24. 1:29OR SUBSTITUTE 5/4 FOR X INTO OUR FUNCTION.
  25. 1:33SO F OF 5/4 IS EQUAL TO -2 x 5/4/SQUARED + 5 x 5/4 + 3.
  26. 1:51WELL 5/4/SQUARED WOULD BE 25/16
  27. 1:54SO WE'LL HAVE -2/1 x 25/16 + 5/1 x 5/4 + 3.
  28. 2:06HERE OUR FACTOR OF 2 SIMPLIFIES.
  29. 2:08THIS SIMPLIFIES TO 1, THIS SIMPLIFIES TO 8.
  30. 2:12SO NOW WE HAVE -25/8 + THIS IS GOING TO BE 25/4
  31. 2:20BUT TO HAVE OUR COMMON DENOMINATOR OF 8
  32. 2:22THIS IS EQUAL TO 50/8 + 3 = 24/8.
  33. 2:31SO NOW WE HAVE A COMMON DENOMINATOR OF 8.
  34. 2:34WE'LL ADD THE NUMERATORS.
  35. 2:35-25 + 50 IS 25 + 24 = 49.
  36. 2:41SO THE Y COORDINATE WOULD BE 49/8.
  37. 2:44WE WILL CONVERT THIS TO A DECIMAL
  38. 2:45WHEN IT COMES TIME TO PLOT THE POINT.
  39. 2:49NOW WE WANT TO FIND THE X AND Y INTERCEPTS OF THE GRAPH.
  40. 2:52SO TO DETERMINE THE X INTERCEPTS OF THE FUNCTION
  41. 2:55WE'RE GOING TO SET Y OR F OF X = 0 AND THEN SOLVE FOR X.
  42. 3:00SO WE WANT TO SOLVE THE EQUATION
  43. 3:010 = -2X/SQUARED + 5X + 3.
  44. 3:12LET'S GO AHEAD AND FACTOR OUT THE NEGATIVE,
  45. 3:14AND THEN SEE IF IT FACTORS.
  46. 3:16FACTORING A NEGATIVE OUT
  47. 3:17IS GOING TO CHANGE THE SIGN OF ALL THE TERMS.
  48. 3:19SO WE'LL HAVE 2X/SQUARED - 5X - 3.
  49. 3:23I THINK THIS WILL FACTOR.
  50. 3:27FACTORS OF 2X/SQUARED WOULD BE 2X AND X.
  51. 3:31NOW WE WANT TO PLACE THE FACTORS OF -3 IN HERE
  52. 3:34SO THAT THE SUM OF THE INNER PRODUCT AND THE OUTER PRODUCT
  53. 3:36WOULD BE -5X.
  54. 3:39SO WE'LL PUT - 3 HERE, THAT'S -6X.
  55. 3:42AND +1 HERE + 1X DOES = -5X.
  56. 3:48SO THIS PRODUCT IS EQUAL TO 0 WHEN 2X + 1 = 0
  57. 3:55OR WHEN X - 3 = 0.
  58. 3:59SO HERE WE'D HAVE X = -1/2 AND HERE WE'D HAVE X = 3.
  59. 4:05THESE ARE THE X INTERCEPTS.
  60. 4:07WE DO WANT TO EXPRESS THESE AS ORDERED PAIRS.
  61. 4:11SO IF THERE ARE TWO X INTERCEPTS,
  62. 4:12ONE OF THEM IS -1/2, 0 AND THE OTHER ONE IS 3, 0.
  63. 4:21NOW TO DETERMINE THE Y INTERCEPT WE WANT TO SET X = 0
  64. 4:25AND THEN SOLVE FOR Y OR SOLVE FOR F OF X.
  65. 4:27WELL IF WE SET X = 0 NOTICE HOW WE WOULD HAVE 0 + 0 + 3
  66. 4:33SO THE Y INTERCEPT IS JUST THE POINT 0, 3.
  67. 4:39SO WHEN WE HAVE A QUADRATIC FUNCTION IN THIS FORM
  68. 4:42THE Y INTERCEPT IS ALWAYS JUST GOING TO BE C.
  69. 4:45NOW LET'S TAKE ALL THIS INFORMATION
  70. 4:46ONTO THE NEXT SLIDE AND CONTINUE.
  71. 4:49NOW WE WANT TO GRAPH THIS FUNCTION.
  72. 4:51LET'S TAKE A LOOK AT THE INFORMATION
  73. 4:53THAT I PROVIDED HERE FROM THE PREVIOUS SLIDE.
  74. 4:55NOTICE FOR THE EQUATION OF THE AXIS, X = 5/4.
  75. 4:59I CONVERTED THIS TO A DECIMAL.
  76. 5:015 DIVIDED BY 4 IS 1.25
  77. 5:04WHICH AGAIN IS THE X COORDINATE OF THE VERTEX
  78. 5:07AND 6.125 IS EQUAL TO 49/8
  79. 5:11WHICH WAS THE Y COORDINATE OF THE VERTEX.
  80. 5:15LET'S START BY SKETCHING THE EQUATION
  81. 5:16OF THE AXIS OF SYMMETRY WHICH IS X = 1.25,
  82. 5:21SOME WHERE IN HERE.
  83. 5:30NEXT LET'S PLOT THE VERTEX WHICH IS ON THIS AXIS,
  84. 5:34HAS THE COORDINATES 1.25, 6.125, SO SOME WHERE IN HERE.
  85. 5:42NEXT, WE'LL PLOT THE INTERCEPTS
  86. 5:44SO WE HAVE THE POINT 3, 0 HERE
  87. 5:47AND WE HAVE THE POINT -1/2, 0 WHICH WOULD BE HERE.
  88. 5:52NOTICE THESE TWO POINTS ARE EQUAL DISTANCE
  89. 5:54TO THE AXIS OF SYMMETRY
  90. 5:57AND THEN WE KNOW THAT THE Y INTERCEPT IS THE POINT 0, 3,
  91. 6:01WHICH WOULD BE THIS POINT HERE.
  92. 6:03THERE MUST A MIRROR IMAGE
  93. 6:04ON THE RIGHT SIDE OF THE AXIS OF SYMMETRY
  94. 6:06SO THERE MUST BE A POINT SOMEWHERE IN HERE
  95. 6:10AND THIS IS MORE THAN ENOUGH INFORMATION
  96. 6:11TO SKETCH A NICE GRAPH OF OUR FUNCTION.
  97. 6:14IT WILL LOOK SOMETHING LIKE THIS.
  98. 6:22NOW WE WANT TO DETERMINE THE DOMAIN AND RANGE
  99. 6:23OF THE FUNCTION.
  100. 6:24REMEMBER THE DOMAIN IS A SET OF ALL POSSIBLE X VALUES
  101. 6:28AND THE RANGE IS THE SET OF ALL POSSIBLE Y VALUES.
  102. 6:33SO AGAIN, DOMAIN MEANS X.
  103. 6:35RANGE MEANS Y.
  104. 6:37WELL THE DOMAIN OF ANY QUADRATIC FUNCTION
  105. 6:39WILL ALWAYS BE ALL REAL NUMBERS,
  106. 6:41WHICH EXPRESSED USING INTERVAL NOTATION
  107. 6:43WOULD BE FROM NEGATIVE INFINITY TO POSITIVE INFINITY.
  108. 6:47LOOKING AT THE GRAPH IT IS MOVING DOWN QUICKLY
  109. 6:50BUT IT'S ALSO MOVING LEFT AND RIGHT FOREVER
  110. 6:52VERIFYING OUR DOMAIN.
  111. 6:54AND THEN FOR THE RANGE OF THE POSSIBLE Y VALUES
  112. 6:56NOTICE HOW THE LARGEST Y VALUE
  113. 6:58IS THE Y COORDINATE OF THE VERTEX WHICH IS 6.125
  114. 7:03AND THEN FROM THERE ALL OF THE Y VALUES ARE LESS THAN THAT.
  115. 7:07SO WE CAN EXPRESS THE RANGE USING INTERVAL NOTATION
  116. 7:11AS THE INTERVAL FROM NEGATIVE INFINITY TO 6.125 OR 49/8
  117. 7:17AND IT DOES INCLUDE THIS VALUE
  118. 7:20SO WE HAVE A CLOSED INTERVAL HERE.
  119. 7:22WE COULD ALSO EXPRESS THIS USING INEQUALITIES
  120. 7:24AS Y IS LESS THAN OR EQUAL TO 49/8.
  121. 7:30AND FOR THE LAST QUESTION
  122. 7:31WE WANT TO DETERMINE THE INTERVALS
  123. 7:32FOR WHICH THE FUNCTION IS INCREASING AND DECREASING.
  124. 7:36SO IF YOU COULD IMAGINE YOURSELF AS A SMALL PERSON
  125. 7:38WALKING ALONG THIS FUNCTION FROM LEFT TO RIGHT,
  126. 7:41IF YOU'RE WALKING UPHILL THE FUNCTION IS INCREASING.
  127. 7:44IF YOU'RE WALKING DOWNHILL THE FUNCTION IS DECREASING.
  128. 7:49BUT IT IS IMPORTANT THAT WE'D BE WALKING FROM LEFT TO RIGHT.
  129. 7:51SO THE FUNCTION IS INCREASING ON THIS INTERVAL
  130. 7:54AND DECREASING ON THIS INTERVAL
  131. 7:56AND IT CHANGES FROM INCREASING TO DECREASING AT THE VERTEX.
  132. 8:01SO THE FUNCTION IS INCREASING ON THE INTERVAL
  133. 8:06FROM NEGATIVE INFINITY
  134. 8:08TO 1.25 THE X COORDINATE OF THE VERTEX.
  135. 8:14REMEMBER 1.25 WAS 5/4 AND IT'S GOING TO BE OPEN ON 5/4
  136. 8:20AND IT'S GOING TO BE DECREASING TO THE RIGHT OF 5/4
  137. 8:23OR THE OPEN INTERVAL FROM 5/4 TO POSITIVE INFINITY.
  138. 8:30OKAY. SO I HOPE YOU FOUND THIS REVIEW HELPFUL.
  139. 8:32THANK YOU FOR WATCHING.

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