Chain Rule For Finding Derivatives — Transcript
Full transcript
- 0:00let's move on to the chain rule we're
- 0:02going to cover a lot of examples the
- 0:05first Formula you need to be familiar
- 0:06with is the derivative of the composite
- 0:09function f of g
- 0:11ofx a composite function is one where
- 0:14you have one function inside of another
- 0:18notice that g is inside of f which makes
- 0:20it a composite function so the first
- 0:23thing you need to do is differentiate
- 0:25the outside portion of the function that
- 0:26is f and you need to keep the inside the
- 0:29same
- 0:30and then multiply it by the derivative
- 0:32of the inside that's the main idea
- 0:34behind the chain rule if you follow this
- 0:37process you're going to get the answer
- 0:38right so let's say for
- 0:41example if we have a function U raised
- 0:44to the N where U is another function in
- 0:46terms of X using the chain Rule and the
- 0:49power rule combined it's going to be n *
- 0:53U you have to keep that the same raised
- 0:55to the N minus one times the derivative
- 0:58of what's on the inside that's the
- 1:00general power rule formula with the
- 1:01chain rule combine so never forget to
- 1:04multiply by the derivative of the inside
- 1:09function so let's use an example let's
- 1:12say if we want to find the
- 1:18derivative of 5x +
- 1:213 raised to the 4th power so the first
- 1:25thing we're going to do is we're going
- 1:26to move the constant I mean the exponent
- 1:28to the front so it's going to be four
- 1:31and then keep the inside stuff the same
- 1:33* 5x + 3 subtract the exponent by 1 4 -
- 1:381 is 3 and then multiply by the
- 1:40derivative of the
- 1:42inside the inside function is four it's
- 1:455x + 3 the derivative of 5x + 3 is just
- 1:495 and so that's the answer we can
- 1:52multiply four and 5 that's going to give
- 1:54us 20 so it's 20 * 5x + 3 ra the thir
- 2:00power so that's the final answer fully
- 2:04simplified now let's work on some more
- 2:07examples find the derivative of x^2 - 3x
- 2:12raised to the 5th
- 2:14power so first let's bring down to five
- 2:17so it's going to be five and then keep
- 2:20the inside function the
- 2:22same and then subtract the exponent by 1
- 2:24so this is four and then multiply by the
- 2:27derivative of the inside the derivative
- 2:29of x^2 - 3x is 2x - 3 and so that's the
- 2:34answer once you get used to the process
- 2:36it's not that
- 2:37bad here's another example that you can
- 2:39try find the derivative of s of
- 2:466X the derivative of the outside part of
- 2:48the function s is cosine and you got to
- 2:51keep the inside function the same then
- 2:54you multiply by the derivative of the
- 2:56inside function the derivative of 6X is
- 2:596 so the answer is simply 6 cosine
- 3:096X now what is the
- 3:12derivative of cosine
- 3:15x^2 so first differentiate the outside
- 3:18part of the function cosine the
- 3:21derivative of cosine is negative sign
- 3:24now the inside part of the function has
- 3:26to remain the same that is the angle of
- 3:28cosine so it's going to be x^2 and then
- 3:32differentiate the inside function x^2
- 3:36which is
- 3:372x so basically you're working away from
- 3:40the outside towards the inside the final
- 3:42answer is
- 3:44-2X sin
- 3:49X2 find the derivative of tangent X CU
- 3:54so first let's differentiate tangent the
- 3:57derivative of tangent is secant squ and
- 4:01the inside function has to remain the
- 4:03same next differentiate the inside
- 4:05function X Cub so that's
- 4:083x^2 and it's always multiplication so
- 4:11it's going to be
- 4:123x^2 secant 2 x
- 4:19Cub as you can see it's not that
- 4:23bad here's another problem what is the
- 4:25derivative of secant 4X
- 4:29the derivative of secant 4X is going to
- 4:32be secant tangent that's the derivative
- 4:34of
- 4:35secant now the inside function has to
- 4:38remain the same for secant and
- 4:40tangent next we need to differentiate 4X
- 4:44so it's just going to be time4 and so
- 4:47that's the
- 4:49solution what is the
- 4:51derivative of Ln X raised to the 7th
- 4:56power try that
- 4:58problem so this is going to be
- 5:01S keep the inside part the same and then
- 5:04subtract the exponent by one so 7 - 1 is
- 5:086 now we got to multiply by the
- 5:10derivative of the inside function the
- 5:13derivative of Ln X is simply 1 /x so the
- 5:16final answer is 7 Ln X raised to 6 power
- 5:21/
- 5:28X What is the dtive of
- 5:32theun of XB -
- 5:357 take a minute and work on that example
- 5:38the first thing I would do is rewrite it
- 5:40so this is the same as X Cub - 7 raised
- 5:44to the
- 5:4712 and so that's going to be equal
- 5:50to2 we got to bring the exponent to the
- 5:53front keep the inside function the same
- 5:56and then subtract the exponent by one 1
- 5:5912 - 1 which is 12 - 2 2 that's a half
- 6:04and then we got to multiply by the
- 6:06derivative of the
- 6:07inside the derivative of x Cub - 7 is
- 6:10simply
- 6:123x^2 so we could bring this back to the
- 6:14bottom since it has a negative exponent
- 6:16so it's 3x^2 / we have a two on the
- 6:20bottom 2 XB - 7 and now the exponent is
- 6:25going to change from negative half to
- 6:27positive half and now we could put it
- 6:30back in its radical form so it's 3x^2 /
- 6:332 < TK XB - 7 and so that's the final
- 6:39answer for this
- 6:41problem find the
- 6:44derivative of 1
- 6:46/ x^2 + 8 raised to the 3
- 6:52power so first let's rewrite the
- 6:56expression let's bring the variables to
- 6:58the top so this is is x^2 + 8 raed Theus
- 7:033 and now we can use the chain
- 7:06rule combined with the power rule let's
- 7:08move the3 to the front and let's keep
- 7:11the inside function let's rewrite it
- 7:13exactly the way we see it and then let's
- 7:15subtract this by 1 -3 - 1
- 7:19is4 and now let's multiply by the
- 7:21derivative of the inside function which
- 7:23is
- 7:242x so now let's take this term move it
- 7:26back to the bottom so we have
- 7:29-3 * 2x which is -6x on top and on the
- 7:35bottom it's x^2 + 8 raised to the 4th
- 7:39power and so that's all we need to do
- 7:41for this
- 7:42problem so for some examples you need to
- 7:45rewrite it before you find the
- 7:51derivative now what if we have a trig
- 7:53function inside another trig
- 7:57function find the Der
- 7:59of this uh
- 8:04function so first we need to
- 8:06differentiate the outside function s the
- 8:09derivative of s is
- 8:11cosine now what's inside of cosine since
- 8:15cosine came from s everything inside of
- 8:18s is going to be the stuff inside of
- 8:21cosine so that's tangent X
- 8:244th now let's move on to tangent the
- 8:27derivative of tangent is secant squ
- 8:30and the stuff that's inside of tangent
- 8:32is going to be the stuff that's inside
- 8:34of secant squ so that's x
- 8:364 and then we got to move on further
- 8:39towards the inside the derivative of x
- 8:414th is 4X cub and so that's the
- 8:46answer how about this example find the
- 8:49derivative of s raised to the 5th
- 8:53power
- 8:56tangent
- 8:57cosine X cub
- 9:01the first thing I would do is rewrite
- 9:02the
- 9:04expression so this is
- 9:06s
- 9:08tangent
- 9:10cosine XB all rais the 5th power so
- 9:14first let's deal with the exponents
- 9:15let's use the power rule so we got to
- 9:18bring the five to the front and keep
- 9:19everything inside the same so always
- 9:23start with the outside portion of the
- 9:25function which is going to be the
- 9:26exponents in this case and then subtract
- 9:29the exponent by one so it's going to be
- 9:31four now let's work our way towards the
- 9:34inside so we got a differentiate sign
- 9:36the derivative of s is cosine and the
- 9:39stuff inside of s is tan cosine X Cub so
- 9:43we got to put that
- 9:50here now let's move on to tangent the
- 9:53derivative of tangent is secant squ and
- 9:56the stuff inside of tan is cosine X cub
- 10:01so hopefully you're seeing a pattern
- 10:03with the way we're finding the
- 10:05derivative of everything so now that
- 10:08we're done with Tangent let's move on to
- 10:10cosine the derivative of cosine is
- 10:13negative sign and the angle of cosine is
- 10:16X Cub so that's going to be the same
- 10:17here and then let's move on to X Cub the
- 10:20derivative of x Cub is
- 10:233x2 so that's the answer and then you
- 10:26can combine terms you can multiply five
- 10:28and three to get 15
- 10:31what is the
- 10:34derivative of cosine raised to the 7th
- 10:37power of
- 10:40s of secant
- 10:43x^2 so try that problem so first let's
- 10:46rewrite it as
- 10:48cosine of s of secant x^2 and let's put
- 10:53the seven and it's exponent position so
- 10:56let's use the power rule let's bring the
- 10:58seven to the front
- 10:59and let's keep everything on the inside
- 11:02the
- 11:07same and then subtract the exponent by
- 11:09one so this is going to be six now let's
- 11:12find the derivative of cosine let's work
- 11:14our way towards the inside the
- 11:16derivative of cosine is negative sign
- 11:18and the stuff inside of that is s
- 11:23secant
- 11:27X2 so now we got to find the Der ative
- 11:31of s the derivative of
- 11:34s is
- 11:37cosine and the stuff inside of s is
- 11:39secant
- 11:41x^2 so now we got to find the derivative
- 11:44of
- 11:44secant so that's secant tangent so it's
- 11:48going to be secant x^2 tangent
- 11:52x^2 and the derivative of x^2 is
- 11:562x so whenever you have multiple
- 11:58composite functions
- 12:00just work your way from the outside
- 12:02towards the inside and everything is
- 12:03multiplied by each
- 12:05other and then when you're done simply
- 12:07collect terms so we have a seven a 2X
- 12:10and a negative so you can move that to
- 12:12the front and write it as -4x if you
- 12:14want
- 12:16to here's the next
- 12:18problem find the derivative of x
- 12:22Cub * 4x + 5 raised to the 4th power
- 12:30so what we have here is a product rule
- 12:33we could say that this is f and this is
- 12:35G and for G we have to use the quotient
- 12:39rule I mean not the quotient rule but
- 12:40the chain rule so using the product rule
- 12:43we need to differentiate the first part
- 12:45F the derivative of the first part is
- 12:483x^2 and we need to keep the second part
- 12:51the same so we just have to rewrite G
- 12:54plus now we need to keep the first part
- 12:56the same now for the second part we need
- 12:58to use the chain room so let's bring the
- 13:00four to the front let's keep the inside
- 13:02stuff the same and subtract the four by
- 13:05one then multiply by the derivative of
- 13:07the inside function which is 4x + 5 the
- 13:10derivative of that is
- 13:12four so now let's simplify so the first
- 13:15part we don't really need to change
- 13:17anything we can just leave it like this
- 13:20now for the second part we can multiply
- 13:22four and four that's 16 so this is 16 x
- 13:26Cub * 4x + 5
- 13:29raised to the thir power you can leave
- 13:31your answer like this or if you want to
- 13:34you can take out the GCF we can take out
- 13:36an x
- 13:38s and we could take out three 4x+ 5S or
- 13:43basically 4x + 5 to the third
- 13:47power so this is gone we took three of
- 13:50these one is left over and we have a a
- 13:52three left so this is going to be a 3 *
- 13:564x + 5
- 13:59and this is gone we took out all three
- 14:01of
- 14:02these well there's an X left over and
- 14:05it's 16 so plus 16 x because we took out
- 14:08an X squ now what we can do is basically
- 14:12simplify what we have
- 14:16here so this is x^2 4x + 5 to the 3
- 14:22power and let's distribute the three so
- 14:243 * 4X is 12x 3 * 5 is 15
- 14:29+
- 14:3116x now let's add 12x and 16x so the
- 14:35final
- 14:36answer is x^2 * 4x + 5 to the 3
- 14:40power and then 28x + 15 so that's the
- 14:48solution let's try one more example
- 14:52let's find the
- 14:53derivative of 2x - 3 / 4 + 5x
- 15:00X raised to the 4th
- 15:04power so this is a chain Rule and
- 15:07quotient rule problem so first we need
- 15:09to bring the exponent down and keep the
- 15:11stuff on the inside the
- 15:14same and then subtract the exponent by
- 15:17one next we need to multiply by
- 15:20derivative of the inside so that's when
- 15:22we have to use a quotient
- 15:24rule so f is 2x - 3 and G
- 15:29is 4 +
- 15:315x frime is 2 G Prime is 4 and the
- 15:36formula for the quotient rule is it's g
- 15:39f Prime minus FG Prime over G ^2 so G is
- 15:454 +
- 15:465x F Prime is
- 15:512 and
- 15:53F is 2x -
- 15:563 G Prime is 4 / g^ 2 which is 4 +
- 16:035x^2 so as you can see this is a long
- 16:12problem so let's simplify what we have
- 16:15on the right side if we distribute the
- 16:18two it's going to be
- 16:208 + 10
- 16:22x and if we distribute the four it's
- 16:25going to be 8X and then * -3 * 4 that's
- 16:34pos2
- 16:35/ 4 +
- 16:395x^2 and then this part is going to be
- 16:42the
- 16:52same so let's simplify the numerator so
- 16:56first we can add 8 and 12
- 16:59so that's going to be 20 and then 10 x -
- 17:028X that's positive 2x / 4 +
- 17:105x^2 now this thing we could distribute
- 17:13the three to the numerator and the
- 17:16denominator so we can write it like this
- 17:17if you want 2x - 3 Cub / 4 + 5x^2 the
- 17:24reason why I did that is because I can
- 17:26now combine these two terms this
- 17:28supposed to be Cube not
- 17:36squared so now what we have is 4 * 2x -
- 17:413 the 3 power and I'm going to take out
- 17:43a two here so if I take out a two it's
- 17:46going to be a x +
- 17:4810 over 4 + 5x raised to the fifth power
- 17:543 + 2 is 5 so the final answer is eight
- 17:594 * 2 is
- 18:018 * x +
- 18:0310 * 2x - 3 to the 3 power / 4 + 5x to
- 18:12the 5th
- 18:13power and so this is the final answer
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